(n): n = abs(n) d21 = n % 100 switch d21: case 11: case 12: case 13: return "th" d1 = n % 10 switch d1: case 1: return "st" case 2: return "nd" case 3: return "rd" default: return "th"This is a bit faster.
suffixmap = new map() { {11, "th"}, {12, "th"}, {13, "th"}, { 1, "st"}, { 2, "nd"}, { 3, "rd"} } (n): n = abs(n) d21 = n % 100 if suffixmap.has(d21): return suffixmap[d21] d1 = n % 10 if suffixmap.has(d1): return suffixmap[d1] return "th"
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